To add to the complexity - there are a couple of other options besides DIGEST and NODIGEST (aka MAIL) - one can also receive notifications just of message subjects that are being discussed: NOHTML INDEX and HTML INDEX. The  the emails received from the ListServ do not contain the text of the messages - they just provide links to the full messages in the list's archives.

I think the INDEX setting is not much used, but we do have an adventurous few that do use it. When I sent:

> Query listname WITH index FOR *@*


13 subscription addresses were returned.

When I sent:

> Query prostate WITH index nomail FOR *@*

An additional 8 addresses were returned, for a total of 21.  (We have about 1230 subscribers)

Charles

On Dec 1, 2015, at 12:54 PM, Bill Kristy wrote:

> Thank you so very much for your reply, Charles!
> 
> Yes a confusing situation; I confess I needed to read that quite a few times.And I think I understand that while the numbers added up for me, I need to break up that last group (WITH NOMAIL FOR *@) in order to to truly separate my Subscribers into:
> 
> A.  Individual message recipients  (aka WITH NODIGEST FOR *@*), 
> B.  Digest Recipients (which I originally thought would be simply WITH DIGEST FOR *@*), and
> C.  Subscribers who don't receive either A or B.
> 
> But I don't know if I understand how..
> 
> My guess is I need to break up the 96 subscribers returned by WITH NOMAIL FOR *@* thusly
> 
> 1.
> WITH NODIGEST NOMAIL FOR *@* (75 subscribers) which is "C"
> 2.
> WITH DIGEST NOMAIL FOR *@* (21 subscribers).  
> 
> And I would add two separate query results
> WITH DIGEST FOR *@*
> +
> WITH DIGEST NOMAIL FOR *@*
> together to get B.
> 
> Wow I'm still not sure I've got it right, so my real question is
> 
> What Queries would I ideally run to reach my goal of finding who is A, B, and C, please?
> 
> Bill

############################

To unsubscribe from the LSTOWN-L list:
write to: mailto:[log in to unmask]
or click the following link:
http://peach.ease.lsoft.com/scripts/wa-PEACH.exe?SUBED1=LSTOWN-L&A=1