On Wed, 15 Jul 1998 09:37:20 -0400, Paul Franco <[log in to unmask]>
wrote:
>
>Anyway, this being the case, is there any way to obtain all members of
>a super-list and its sub-lists?
>
The only way is REVIEW superlist, REVIEW sublistA, REVIEW sublistB, etc.
Naturally this will not eliminate any duplicates from the total listing.